wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The above is a plot of binding energy per nucleon Eb, against the nuclear mass M; A, B, C, D, E, F correspond to different nuclei. Consider four reactions;
[AIEEE-2009]

(i) A + B → C + E (ii) C → A + B + E
(iii) D + E → F + E (iv) F → D + E + E

Where ε is the energy released? In which reactions is ε positive?

A
(i) and (iv)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(i) and (iii)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(ii) and (iv)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(ii) and (iii)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (i) and (iv)
Look at the graph

Now, from the options, option (iii)
D + E F + E

can be clearly ruled out, as D has much more binding energy them F.

Now, let us consider
(i) A + B → C + E
(ii) C → A + B + E
(iv) F → D + E + E
(iv) is obviously gonna release positive energy as F has much lesser. Binding energy / nuclear than C + E + F

Similarly (i) is also gonna have positive release of energy.

Whereas, (ii) is not, as A has a very less Binding energy.

i.e., (i) & (iv) are the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon