CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
463
You visited us 463 times! Enjoying our articles? Unlock Full Access!
Question

The abscissa of two points A and B are the roots of the equation x2+2ax−b2 and their ordinates are the root of the equation x2+2px−q2=0. the equation of the circle with AB as diameter is

A
x2+y2+2ax+2py+b2+q2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x2+y22ax2pyb2q2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+y2+2ax+2pyb2q2=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D x2+y2+2ax+2pyb2q2=0
x2+2axb2=0

Let roots be x1 & x2

x1+x2=ba=2a
x1x2=ca=b2
x2+2pxq2=0

Let roots be y1 & y2

y1+y2=2p
y1y2=q2

Equation in diametric form is
x2+y2(x1+x2)x(y1+y2)y+x1x2+y1y2=0
x2+y2+2ax+2pyb2q2=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Circle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon