The absolute difference between two linear factors of
$x^{2} + 4 x y + 4 y^{2} + x + 2 y$ is:

0

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1

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2

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3

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Solution

The correct option is B $1$
$\Rightarrow x^{2} + 4 x y + 4 y^{2} + x + 2 y$
$\Rightarrow (x + 2 y)^{2} + (x + 2 y)^{1}$
Base are same so
$\Rightarrow 2 - 1 = 1$
The absolute difference between two linear factors is $1$

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