The absolute permeability of a medium is 8.792 x 10 $^{- 6}$ henry/m. Its relative permeability is:

0.7

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6 x 10

^{- 8}

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Solution

The correct option is C 7
$μ_{r} = \frac{μ}{μ_{0}} = \frac{8.792 \times 10^{- 6}}{1.2566 \times 10^{- 6}} = 7$

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The absolute permeability of a medium is 8.792 x 10−6 henry/m. Its relative permeability is:

The correct option is C 7μr=μμ0=8.792×10−61.2566×10−6=7

The absolute permeability of a medium is 8.792 x 10 $^{- 6}$ henry/m. Its relative permeability is:

The correct option is C 7
$μ_{r} = \frac{μ}{μ_{0}} = \frac{8.792 \times 10^{- 6}}{1.2566 \times 10^{- 6}} = 7$