The absolute refractive index of water is 43- What is the critical angle-

Given: the absolute refractive index of water is 43 To find the critical angleSolution:Let the critical angle be C .According to Snell #8217;s Law, ...

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Physics

Critical Angle

The absolute ...

Question

The absolute refractive index of water is $\frac{4}{3}$ . What is the critical angle?

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Solution

Given: the absolute refractive index of water is $\frac{4}{3}$
To find the critical angle
Solution:
Let the critical angle be $C$ .
According to Snell’s Law,
$C = {sin}^{- 1} (\frac{1}{μ}) ⟹ C = {sin}^{- 1} (\frac{3}{4}) ⟹ C = {48.59}^{\circ}$
is the required critical angle.

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The absolute refractive index of water is 43. What is the critical angle?

Given: the absolute refractive index of water is 43To find the critical angleSolution:Let the critical angle be C.According to Snell’s Law, C=sin−1(1μ)⟹C=sin−1(34)⟹C=48.59∘is the required critical angle.

The absolute refractive index of water is $\frac{4}{3}$ . What is the critical angle?

Given: the absolute refractive index of water is $\frac{4}{3}$
To find the critical angle
Solution:
Let the critical angle be $C$ .
According to Snell’s Law,
$C = {sin}^{- 1} (\frac{1}{μ}) ⟹ C = {sin}^{- 1} (\frac{3}{4}) ⟹ C = {48.59}^{\circ}$
is the required critical angle.