The absorption maximum for the complex ion $[C o (N H_{3})_{6}]^{3 +}$ occurs at $470 n m$ . The crystal field splitting in $J / m o l$ is $x$ then write the nearest integer value of $\frac{x}{5 \times 10000}$ .

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Solution

The crystal field splitting energy for the complex ion is
$E = \frac{h c}{λ} = \frac{6.626 \times 10^{- 34} \times 3 \times 10^{8}}{470 \times 10^{- 9}} = 4.23 \times 10^{- 19} J$
The crystal field energy for 1 mole is
$4.23 \times 10^{- 19} \times 6.023 \times \times 10^{23} = 254773 J / m o l$

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Similar questions

[T i (N C S)_{6}]^{3 -}

ion exhibits a single absorption band at 544 nm. What will be the crystal field splitting energy (in kJ/mol) of the complex ?

(h = 6.626 \times 10^{- 34} J s; c = 3 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e)

Q. The

[T i (N C S)_{6}]^{3 -}

ion exhibits a single absorption band at

544 n m

. If the crystal field splitting energy is

21979 \times 10^{- x} k J . m o l^{- 1}

, then find the value of x.

Q. The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes,

[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}

[T i (N C S)_{6}]^{3 -}

ion exhibits a single absorption band at 544 nm. What will be the crystal field splitting energy (in kJ/mol) of the complex ?

(h = 6.626 \times 10^{- 34} J s; c = 3 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e)

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

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The absorption maximum for the complex ion [Co(NH3)6]3+ occurs at 470nm. The crystal field splitting in J/mol is x then write the nearest integer value of x5×10000.

The crystal field splitting energy for the complex ion is E=hcλ=6.626×10−34×3×108470×10−9=4.23×10−19J The crystal field energy for 1 mole is 4.23×10−19×6.023××1023=254773 J/mol

The absorption maximum for the complex ion $[C o (N H_{3})_{6}]^{3 +}$ occurs at $470 n m$ . The crystal field splitting in $J / m o l$ is $x$ then write the nearest integer value of $\frac{x}{5 \times 10000}$ .

The crystal field splitting energy for the complex ion is
$E = \frac{h c}{λ} = \frac{6.626 \times 10^{- 34} \times 3 \times 10^{8}}{470 \times 10^{- 9}} = 4.23 \times 10^{- 19} J$
The crystal field energy for 1 mole is
$4.23 \times 10^{- 19} \times 6.023 \times \times 10^{23} = 254773 J / m o l$