The absorption transition between the first and the fourth energy states of hydrogen atom are $3$ . The emission transition between these states will be:

3

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4

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5

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6

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Solution

The correct option is D $6$
Number of emission states are:

$4 t o 3$

$4 t o 2$

$4 t o 1$

$3 t o 2$

$3 t o 1$

$2 t o 1$

So, number of emission states are $6$ .

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The absorption transition between the first and the fourth energy states of hydrogen atom are 3. The emission transition between these states will be:

The correct option is D 6Number of emission states are: 4to3 4to2 4to1 3to2 3to1 2to1 So, number of emission states are 6.

The absorption transition between the first and the fourth energy states of hydrogen atom are $3$ . The emission transition between these states will be:

The correct option is D $6$
Number of emission states are:

$4 t o 3$

$4 t o 2$

$4 t o 1$

$3 t o 2$

$3 t o 1$

$2 t o 1$

So, number of emission states are $6$ .