Question

The absorption transition between the first and the fourth energy states of hydrogen atom are $3$. The emission transitions between these states will be,

• A. $3$
• B. $4$
• C. $5$
• D. $6$

Answer 1

The correct option is D $6$

Since, the absorption transition between the first and the fourth energy states of hydrogen atom are given as $3$ then, the emission transition between these states is given by,
$N_E=\frac{n(n-1)}{2}\Rightarrow N_E=\frac{4(4-1)}{2}=6$

Hence, $\left(D\right)$ is the correct answer.

Why this question? This question is based on absorption and emission spectrum lines.