The ac current gain of a transistor is $120$ . What is the change in the collector current in the transistor whose base current changes by $100 μ A$ ?

6 m A

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12 m A

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3 m A

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24 m A

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Solution

The correct option is B $12 m A$
Given that,

Current gain $β = 120 A$

Base current $Δ I_{b} = 100 μ A$

We know that,

$β_{a c} = \frac{Δ I_{C}}{Δ I_{B}}$

$Δ I_{C} = 120 \times 100 \times 10^{- 6}$

$Δ I_{C} = 12 \times 10^{- 3} A$

$Δ I_{C} = 12 m A$

Hence, the collector current in the transistor is $12 m A$

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The ac current gain of a transistor is 120. What is the change in the collector current in the transistor whose base current changes by 100 μA?

The correct option is B 12 mAGiven that, Current gainβ=120A Base current ΔIb=100μA We know that, βac=ΔICΔIB ΔIC=120×100×10−6 ΔIC=12×10−3A ΔIC=12mA Hence, the collector current in the transistor is 12 mA

The ac current gain of a transistor is $120$ . What is the change in the collector current in the transistor whose base current changes by $100 μ A$ ?