The acceleration a (in ms−2) of a body, starting from rest varies with time t (in s) following the equation a=3t+4. The velocity of the body at time t=2s will be
A
10ms−1
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B
18ms−1
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C
14ms−1
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D
26ms−1
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Solution
The correct option is C14ms−1 Given a=3t+4 ⇒dvdt=3t+4 ∴∫v0dv=∫t0(3t+4)dt ⇒v=32t2+4t at t=2s v=32(2)2+4(2)=14ms−1