The acceleration due to gravity on the moon is $1 / 6 t h$ of that on the earth. If a man can jump upto a height of $1 m$ on the surface of the earth, how high he can jump on the surface of the moon?

3 m

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4 m

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6 m

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8 m

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Solution

The correct option is C $6 m$
Potential energy is constant

$m g h_{e} = m \frac{g}{6} h_{m} (w h e r e, h_{e} = h e i g h t o n e a r t h, h_{m} = h e i g h t o n m o o n)$

$h_{m} = 6 h_{e} = 6 \times 1 = 6 m$

Hence, he can jump $6 m$ high on moon.

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The acceleration due to gravity on the moon is 1/6th of that on the earth. If a man can jump upto a height of 1 m on the surface of the earth, how high he can jump on the surface of the moon?

The correct option is C 6 mPotential energy is constant mghe=mg6hm(where,he=heightonearth,hm=heightonmoon) hm=6he=6×1=6m Hence, he can jump 6m high on moon.

The acceleration due to gravity on the moon is $1 / 6 t h$ of that on the earth. If a man can jump upto a height of $1 m$ on the surface of the earth, how high he can jump on the surface of the moon?

The correct option is C $6 m$
Potential energy is constant

$m g h_{e} = m \frac{g}{6} h_{m} (w h e r e, h_{e} = h e i g h t o n e a r t h, h_{m} = h e i g h t o n m o o n)$

$h_{m} = 6 h_{e} = 6 \times 1 = 6 m$

Hence, he can jump $6 m$ high on moon.