The acceleration due to gravity on the moon is one-sixth that on the earth. If a high jumper can jump $2 m$ on earth, then what distance can he jump on the moon?

2 m

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12 m

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6 m

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8 m

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Solution

The correct option is A $12 m$
The reason why we come down when jumping is the gravitational pull. Let's imagine that $F$ force was required for us to jump $2 m$ with $g$ gravitational force. Mathematically,
$g$ generates $2 m$ of height in jump.
We know, $P . E \propto g h$ (as potential energy= $m g h$ and mass and energy will be constant)
When $g$ changes to $\frac{g}{6}$ , the potential energy will still be the same.
Hence, $m g h_{1} = m \frac{g}{6} h_{2}$
or, $h_{2} = 2 \times 6 = 12 m$ , which is our required answer.

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The acceleration due to gravity on the moon is one-sixth that on the earth. If a high jumper can jump 2m on earth, then what distance can he jump on the moon?

The acceleration due to gravity on the moon is one-sixth that on the earth. If a high jumper can jump $2 m$ on earth, then what distance can he jump on the moon?