Question

The acceleration due to gravity on the surface of a planet, whose mass and diameter are double that of the earth, is____ $\times {10}^{-1}$ times the acceleration due to gravity on the surface of the earth.

• A. 5
• B. 3
• C. 0.5
• D. 50

Answer 1

The correct option is A 5

Acceleration due to gravity on the earth surface is given by

$g=\frac{GM}{r^2}$...(1)

On planet having mass $2M$ and r\Redius $R$

$g_p=\frac{G\left(2M\right)}{(2r{)}^2}$

From equation (1)

$g_p=0.5g=5\times {10}^{-1}g$

so correct option is A.