The acceleration d 2 x - d t2 of a particle varies with displacement x as d 2 x - d 2- kx- where k is a constant of the motion- The time period T of the motion is equaltoA- 2 - kB- 2 -kC- 2 -kD- 27-k

The correct option is C x = a sin (ω t + ϕ ) T =2π√(displacement/acceleration) T =2π√(x/kx)=2π√(1/k) ...

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Simple Harmonic Oscillation

The accelerat...

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The acceleration $\frac{d^{2} x}{d t^{2}}$ of a particle varies with displacement x as $\frac{d^{2} x}{d t^{2}} = - k x$ , where k is a constant of the motion.The time period T of the motion is equal to

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