Question

The acceleration of a car that speeds up from 12 meters per second to 30 meters per second in 15 seconds-

• A. $2.4\mathrm{m}/{\mathrm{s}}^2$
• B. $1.2\mathrm{m}/{\mathrm{s}}^2$
• C. $2\mathrm{m}/{\mathrm{s}}^2$
• D. $5.2\mathrm{m}/{\mathrm{s}}^2$

Answer 1

The correct option is B

$1.2\mathrm{m}/{\mathrm{s}}^2$

Step 1: Given data,

As per the data given,

Initial velocity, $u=12m/s$

Final velocity,$v=30m/s$

Time taken, $t=15s$

Step 2: To calculate the acceleration of the car,

We know that, according to the first equation of motion,

$v=u+at$

Here v is final velocity and u is initial velocity and a is acceleration and t is time.

After substituting the values-

$30=12+a\times 15$

$15a=30-12=18$

$a=\frac{18}{15}=1.2m/s^2$

Thus, the acceleration of the car is $1.2m/s^2$.

Hence, option B is the correct answer.