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Standard XII

Physics

Power, Force and Velocity

The accelerat...

Question

The acceleration of a particle as a function of time $t$ is given as $a = k . t^{5 / 2}$ . If initial speed of the particle $(a t t = 0)$ is $u$ then its velocity $v$ as a function of time $t$ is given as :

v = u + \frac{2}{5} k t^{5 / 2}

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v = u + \frac{2}{7} k t^{7 / 2}

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v = u + k t^{5 / 2}

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v = u + k t^{7 / 2}

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Solution

The correct option is D $v = u + k t^{7 / 2}$
Given,

$u =$ initial velocity

$a = k . t^{5 / 2}$

$v =$ final velocity after time $t$

1st equation of motion,

$v = u + a t$

$v = u + k . t^{5 / 2} t$

$v = u + k . t^{7 / 2}$

The correct option is D.

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The acceleration of a particle as a function of time t is given as a=k.t5/2. If initial speed of the particle (at t=0) is u then its velocity v as a function of time t is given as :

The correct option is D v=u+kt7/2Given,u= initial velocitya=k.t5/2v= final velocity after time t1st equation of motion,v=u+atv=u+k.t5/2tv=u+k.t7/2The correct option is D.

The acceleration of a particle as a function of time $t$ is given as $a = k . t^{5 / 2}$ . If initial speed of the particle $(a t t = 0)$ is $u$ then its velocity $v$ as a function of time $t$ is given as :

The correct option is D $v = u + k t^{7 / 2}$
Given,

$u =$ initial velocity

$a = k . t^{5 / 2}$

$v =$ final velocity after time $t$

1st equation of motion,

$v = u + a t$

$v = u + k . t^{5 / 2} t$

$v = u + k . t^{7 / 2}$

The correct option is D.