The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17m/s when x=0, then the velocity of the particle when x=4m is
A
12m/s
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B
15m/s
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C
20m/s
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D
25m/s
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Solution
The correct option is B15m/s Given, a=−4x(−1+14x2)=vdvdx ⇒∫v17vdv=∫40(4x−x3)dx ⇒12[v2]v17=42[x2]40−14[x4]40 ⇒v2−172=4(42−0)−12(44−0) ⇒v2=225 ⇒v=15m/s