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Question

The acceleration of a particle is defined by the relation, a=4x(1+14x2) , where x is displacement along x axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is

A
12 m/s
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B
15 m/s
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C
20 m/s
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D
25 m/s
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Solution

The correct option is B 15 m/s
Given,
a=4x(1+14x2)=vdvdx
v17vdv=40(4xx3)dx
12[v2]v17=42[x2]4014[x4]40
v2172=4(420)12(440)
v2=225
v=15 m/s

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