The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with an initial velocity v0. The distance travelled by the particle in time t will be
A
v0t+16bt3
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B
v0t+12bt2
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C
v0t+13bt3
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D
v0t+13bt2
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Solution
The correct option is Av0t+16bt3 a=bt v=∫a⋅dt=∫bt⋅dt v(t)=bt22+v0 s=∫v⋅dt=bt36+v0t+0 s(t)→bt36+v0t