The acceleration of a particle starting from rest vary with respect to time is given by a = (2t - 6), where t is in seconds. Find the time at which velocity of particle in negative direction is maximum.
integrating both sides we get
velocity =0 when t^2-6t=0
=>either at t=0 or t=6
So velocity is negative between t=0 and t=6
=>velocity in negative direction will be maximum
Velocity in negative direction is maximum when t=3s
and maximum negative velocity=t^2-6t=9-18= -9m/s