The acceleration of an electron placed in an electric field of strength 18.2 x $10^{- 6}$ N C $^{- 1}$ is _______ms $^{- 2}$

1.6

10^{6}

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3.2

10^{6}

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6.4

10^{6}

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1.2

10^{4}

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Solution

The correct option is B $3.2$ x $10^{6}$
Force on the electron $= F = q E = e E$

Acceleration of the electron $a = \frac{F}{m} = \frac{e E}{m_{e}}$

$⟹ a = \frac{1.6 \times 10^{- 19} \times 18.2 \times 10^{- 6}}{9.1 \times 10^{- 31}}$

$⟹ a = 3.2 \times 10^{6} m s^{- 2}$

Answer-(B)

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The acceleration of an electron placed in an electric field of strength 18.2 x 10−6 N C−1 is _______ms−2

The correct option is B 3.2 x 106Force on the electron=F=qE=eEAcceleration of the electrona=Fm=eEme⟹a=1.6×10−19×18.2×10−69.1×10−31⟹a=3.2×106ms−2Answer-(B)

The acceleration of an electron placed in an electric field of strength 18.2 x $10^{- 6}$ N C $^{- 1}$ is _______ms $^{- 2}$

The correct option is B $3.2$ x $10^{6}$
Force on the electron $= F = q E = e E$

Acceleration of the electron $a = \frac{F}{m} = \frac{e E}{m_{e}}$

$⟹ a = \frac{1.6 \times 10^{- 19} \times 18.2 \times 10^{- 6}}{9.1 \times 10^{- 31}}$

$⟹ a = 3.2 \times 10^{6} m s^{- 2}$

Answer-(B)