The acceleration of free fall for object moving near the surface of Earth is:

9.81 m s^{- 2}

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9.31 m s^{- 2}

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8.81 m s^{- 2}

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10.81 m s^{- 2}

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Solution

The correct option is D $9.81 m s^{- 2}$
Acceleration of free fall is when only acceleration due to gravity is acting on the body is 9.81 $m / s^{2}$

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The acceleration of free fall for object moving near the surface of Earth is:

The correct option is D 9.81ms−2Acceleration of free fall is when only acceleration due to gravity is acting on the body is 9.81 m/s2

The correct option is D $9.81 m s^{- 2}$
Acceleration of free fall is when only acceleration due to gravity is acting on the body is 9.81 $m / s^{2}$