Question

The acceleration of point on the rim of flywheel 1m in diameter, if it makes $1200revolutionsperminute$ is

• A. $8{\pi }^2{m/s}^2$
• B. $80{\pi }^2{m/s}^2$
• C. $800{\pi }^2{m/s}^2$
• D. None of these

Answer 1

The correct option is C $800{\pi }^2{m/s}^2$

Given $\omega =1200$ rev/min
$=1200\times \frac{2\pi }{60}$
$=40\pi rad/s$
Given radius $=0.5m$
Centripetal acceleration $=r{\omega }^2$
$=0.5\times 1600{\pi }^2$
$a_r=800{\pi }^2$