A particle is moving in a straight line with initial velocity of 10 $\frac{m}{s}$ . Acceleration - Time graph of the particle is shown in the figure. Find velocity at t = 10 seconds.

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The acceleration of the particle moving in positive x−direction with an initial velocity of 10 m/s is 3 m/s2. Its velocity at t=4 sec is

The correct option is B 22 m/sGiven, a=3 m/s2,u=10 m/s and t=4 sec Using first equation of motion we have v=u+at ⇒ v=10+3×4=22 m/s Hence, velocity at t=4 sec is 22 m/s.

The acceleration of the particle moving in positive $x -$ direction with an initial velocity of $10 m / s$ is $3 m / s^{2}$ . Its velocity at $t = 4 s e c$ is

The correct option is B $22 m / s$
Given, $a = 3 m / s^{2}, u = 10 m / s and t = 4 s e c$
Using first equation of motion we have
$v = u + a t$
$\Rightarrow v = 10 + 3 \times 4 = 22 m / s$
Hence, velocity at $t = 4 s e c$ is $22 m / s$ .