The acceleration of the particle moving in positive x− direction with an initial velocity of 20m/s is 4m/s2. Its velocity at t=5sec is
A
22m/s
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B
40m/s
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C
30m/s
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D
25m/s
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Solution
The correct option is B40m/s Given, a=4m/s2,u=20m/sandt=5sec
Using first equation of motion we have v=u+at ⇒v=20+4×5=40m/s
Hence, velocity at t=5sec is 40m/s.