The acceleration of the particle moving in positive x−direction with an initial velocity of 10m/s is 3m/s2. Its velocity at t=4sec is
A
20m/s
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B
22m/s
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C
24m/s
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D
18m/s
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Solution
The correct option is B22m/s Given, a=3m/s2,u=10m/sandt=4sec
Using first equation of motion we have v=u+at ⇒v=10+3×4=22m/s
Hence, velocity at t=4sec is 22m/s.