The acceleration-time graph of a body is shown below. If initial velocity of body is 20m/s, then velocity of body after 10s is
A
20ms−1
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B
40ms−1
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C
50ms−1
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D
70ms−1
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Solution
The correct option is D70ms−1 The area under the acceleration-time graph gives the change in velocity in that time interval. Therefore in 10s, the change in velocity is =5×10=50ms–1. Since the initial velocity is 20ms−1 and acceleration is positive the final velocity would therefore be 50+20=70ms–1