The acceleration - time graph of a particle moving along a straight line is as shown in the figure. At what time the particle acquires its initial velocity?
A
12s
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B
5s
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C
8s
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D
16s
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Solution
The correct option is C8s We know that under area under a−t graph represents change in velocity.
Let A1 and A2 be the areas of upper and lower triangle respectively.
Particle will acquire the initial velocity again when, A1+A2=0⇒|A1|=|A2| A1=12×10×4=20 A2=12×(to−4)×(−x)=20 ⇒x(to−4)=40(1)
Since the slope of line remains same, ∴104=−xto−4(2)
Solving (1) and (2), we get x=−10 and to=8s
Hence particle will acquire its initial velocity at 8s