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Question

# The acceleration versus time graph for a particle moving along a straight line is shown in the figure. If the particle starts from rest at t=0, then its speed at t=30 s will be

A
20 m/s
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B
0 m/s
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C
40 m/s
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D
60 m/s
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Solution

## The correct option is C −40 m/sFor a−t curve, area under the graph = change in velocity. Total area under the graph from t=0 to t=30 s is given by A= Area of the graph from t=0 to t=10 s + Area of the graph from t=10 s to t=30 s ⇒A=4×10−20×4=−40 m/s Now, A=Δv (where Δv is change in velocity) ⇒−40=v30−v0 As v0=0 ∴v30=−40 m/s Hence, speed of the particle at 30 s=−40 m/s

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