The accelerations of the blocks A and B in the situation shown in the figure are:
From
FBD,
Lets a be the acceleration.
For 5kg block , 5a=2T−50....(1)
For 4kg block, 4(2a)=40−T....(2)
Solving (1),(2),
5a=2(40−8a)−50
or,21a=30⇒a=3021=107=g7
Acceleration of
block A =2a=2g7
Acceleration of block B
=a=g7