Question

The acid obtained where ${\mathrm{P}}_4{\mathrm{O}}_6$ reacts with water is:

Answer 1

Part 1: Formation of ${\mathrm{P}}_4{\mathrm{O}}_6$

Phosphoric acid is formed when ${\mathrm{P}}_4{\mathrm{O}}_6$interacts with water.

Phosphorus trioxide is the chemical name for ${\mathrm{P}}_4{\mathrm{O}}_6$

It’s made by burning phosphorus in a low-oxygen environment. The following is the reaction:
$\underset{\mathrm{Phosphorous}}{{\mathrm{P}}_4\left(\mathrm{s}\right)}+\underset{\mathrm{Oxygen}}{3{\mathrm{O}}_2\left(\mathrm{g}\right)}\to \underset{\mathrm{Phosphorus}\mathrm{Hexaoxide}}{{\mathrm{P}}_4{\mathrm{O}}_6\left(\mathrm{s}\right)}$

Part 2: Reaction of water with ${\mathrm{P}}_4{\mathrm{O}}_6$

When this product comes into contact with water, it produces phosphorous acid, ${\mathrm{H}}_3{\mathrm{PO}}_3$ is the chemical formula for phosphoric acid.

The following is how the reaction happens:
$\underset{\mathrm{Phosphorous}\mathrm{Hexaoxide}}{{\mathrm{P}}_4{\mathrm{O}}_6\left(\mathrm{s}\right)}+\underset{\mathrm{Water}}{6{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}\to \underset{\mathrm{Phosphoric}\mathrm{Acid}}{4{\mathrm{H}}_3{\mathrm{PO}}_3\left(\mathrm{s}\right)}$