The acid strength of active methylene group in given compounds decreases as : (a) CH3COCH2COOC2H5 (b) CH3COCH2COCH3 (c) C2H5OOCCH2COOC2H5
A
a>b>c
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B
c>a>b
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C
a>c>b
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D
b>a>c
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Solution
The correct option is Db>a>c +I effect in ester is more compared to ketone hence methylene anion will be more stable in case of ketone leading to more stable anion and more acidity.