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Empirical & Molecular Formula

The acidic, a...

Question

The acidic, aqueous solution of ferrous ion forms a brown complex in the presence of ${N O}_{3}^{-}$ by the following two steps. Complete and balance the equations:

$[{F e (H_{2} O)}_{6}]^{2 +} + {N O}_{3}^{-} + H^{+} ⟶ (a) + {F e (H_{2} O)}_{6}]^{3 +} + H_{2} O$

$[{F e (H_{2} O)}_{6}]^{2 +} + (b) ⟶ (c) + H_{2} O$

The product c is $[F e (H_{2} O)_{5} N O]^{2 +}$

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Solution

The acidic, aqueous solution of ferrous ion forms a brown complex in the presence of ${N O}_{3}^{-}$ by the following two steps.
$6 [{F e (H_{2} O)}_{6}]^{2 +} + {2 N O}_{3}^{-} + {6 H}^{+} ⟶ (2 N O) + {6 F e (H_{2} O)}_{6}]^{3 +} + {4 H}_{2} O$
$[{F e (H_{2} O)}_{6}]^{2 +} + (N O) ⟶ ([F e (H_{2} O)_{5} N O]^{2 +}) + H_{2} O$

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