wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The activation energy for a reaction at the temperature TK was found to be 2.303 RTJmol1. The ratio of the rate constant to Arrhenius factor is ___


A

102

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

101

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

2×102

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2×103

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

101


k=AeEaRT
Ea=2.303RT
kA=e(2.303RTRT);kA=e2.303
loge(kA)=loge e2.303
loge(kA)=2.303 or 2.303log10(kA)=2.303
log(kA)=1;log(AK)=1
Ak=anti log1=10 or kA=110=101


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arrhenius Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon