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Question

The activation energy for a reaction at the temperature TK was found to be 2.303 RTJmol1. The ratio of the rate constant to Arrhenius factor is ___

A
102
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B
101
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C
2×102
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D
2×103
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Solution

The correct option is B 101
k=AeEaRT
Ea=2.303RT
kA=e(2.303RTRT);kA=e2.303
loge(kA)=loge e2.303
loge(kA)=2.303 or 2.303log10(kA)=2.303
log(kA)=1;log(AK)=1
Ak=anti log1=10 or kA=110=101

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