Question

The activation energy for souring of milk in (kcal) is :

• A. $10.454$ kcal
• B. $16.654$ kcal
• C. $12.540$ kcal
• D. none of the above

Answer 1

Answer: (A)

$10.454$ kcal

Given: $\frac{K_{293}}{K_{276}}=3;T_2=293K$ and $T_1=276K$

$2.303lo{g}_{10}\frac{K_2}{K_1}=\frac{E_a}{R}\frac{[T_2-T_1]}{T_1{T}_2}(R=2cal)$

$\therefore 2.303lo{g}_{10}3=\frac{E_a}{2}\frac{[293-276]}{293\times 276}$

$\therefore E_a=10453.95cal=10.454kcal$