The activation energy for the forward reaction X Y is 60 KJ mol-1 and - H is -20 KJ mol-1- The activation energy for the backward reaction Y X is-

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Standard XII

Chemistry

Activation Energy

The activatio...

Question

The activation energy for the forward reaction X Y is $60$ KJ $m o l^{- 1}$ and $Δ H$ is $- 20$ KJ $m o l^{- 1}$ . The activation energy for the backward reaction Y X is:

80

m o l^{- 1}

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40

m o l^{- 1}

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60

m o l^{- 1}

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20

m o l^{- 1}

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Solution

The correct option is B $80$ kJ $m o l^{- 1}$
We know that,
$Δ H = E_{f} - E_{b}$

$- 20 = 60 - E_{b}$

$E_{b} = (60 + 20) K J / m o l$

$= 80 K J m o l^{- 1}$

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The activation energy for the forward reaction X Y is 60 KJ mol−1 and ΔH is −20 KJ mol−1. The activation energy for the backward reaction Y X is:

The correct option is B 80 kJ mol−1We know that,ΔH=Ef−Eb−20=60−EbEb=(60+20)KJ/mol=80KJmol−1

The activation energy for the forward reaction X Y is $60$ KJ $m o l^{- 1}$ and $Δ H$ is $- 20$ KJ $m o l^{- 1}$ . The activation energy for the backward reaction Y X is:

The correct option is B $80$ kJ $m o l^{- 1}$
We know that,
$Δ H = E_{f} - E_{b}$

$- 20 = 60 - E_{b}$

$E_{b} = (60 + 20) K J / m o l$

$= 80 K J m o l^{- 1}$