The activation energy for the forward reaction X Y is 60 KJ mol-1 and - H is -20 KJ mol-1- The activation energy for the backward reaction Y X is-

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Activation Energy

The activatio...

Question

The activation energy for the forward reaction X Y is $60$ KJ $m o l^{- 1}$ and $Δ H$ is $- 20$ KJ $m o l^{- 1}$ . The activation energy for the backward reaction Y X is:

80

m o l^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40

m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60

m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20

m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $80$ kJ $m o l^{- 1}$
We know that,
$Δ H = E_{f} - E_{b}$

$- 20 = 60 - E_{b}$

$E_{b} = (60 + 20) K J / m o l$

$= 80 K J m o l^{- 1}$

Suggest Corrections

Similar questions

Q. The activation energy for the forward reaction

X

\to

Y

60 k J

m o l^{- 1}

and

Δ H

- 20 k J

m o l^{- 1}

. The activation energy for the reverse reaction is:

For the reaction $A + B \to C + D Δ H = - 20 k J m o l^{- 1}$ . The activation energy of the forward reaction is $85 k J m o l^{- 1}$ . The activation energy for backward reaction is

Q. In a reversible reaction, the enthalpy change and the activation energy in the forward direction are respectively

- x k J m o l^{- 1}

and

y k J m o l^{- 1}

. Therefore, the energy of activation in the backward direction, in

k J m o l^{- 1}

is:

In an exothermic reaction $A \to B$ , the activation energy of reverse reaction is twice that of forward reaction. If enthalpy of the reaction is -80 kJ $m o l^{- 1}$ , the activation energy of the reverse reaction is :

Join BYJU'S Learning Program

The activation energy for the forward reaction X Y is 60 KJ mol−1 and ΔH is −20 KJ mol−1. The activation energy for the backward reaction Y X is:

The correct option is B 80 kJ mol−1We know that,ΔH=Ef−Eb−20=60−EbEb=(60+20)KJ/mol=80KJmol−1

The activation energy for the forward reaction X Y is $60$ KJ $m o l^{- 1}$ and $Δ H$ is $- 20$ KJ $m o l^{- 1}$ . The activation energy for the backward reaction Y X is:

The correct option is B $80$ kJ $m o l^{- 1}$
We know that,
$Δ H = E_{f} - E_{b}$

$- 20 = 60 - E_{b}$

$E_{b} = (60 + 20) K J / m o l$

$= 80 K J m o l^{- 1}$