Question

The active mass of 64 g of HI in two litre flask will be:

• A. 2
• B. 1
• C. 5
• D. 0.25

Answer 1

The correct option is D 0.25

Active mass = number of moles/volume of solution
Molar mass of $HI=128,\frac{64}{128}=0.5\frac{0.5}{2}=0.25Molmass=128$