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Question

The active mass of 64 g of HI in two litre flask will be:

A
2
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B
1
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C
5
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D
0.25
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Solution

The correct option is D 0.25
Active mass = number of moles/volume of solution
Molar mass of HI=128,64128=0.50.52=0.25 Mol mass =128

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