The active species in the nitration of benzene is:

{N O}_{2}^{+}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{H N O}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{N O}_{3}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{N O}_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ${N O}_{2}^{+}$
In nitration of benzene nitrating mixture is used. Which produce $N O_{2}^{+}$ as below.
${H N O}_{3} + H_{2} {S O}_{4} ⟶ {H S O}_{4}^{-} + H_{2} {N O}_{3}^{+} H_{2} {N O}_{3}^{+} ⟶ H_{2} O + {N O}_{2}^{+}$
${N O}_{2}^{+}$ is active species in the nitration of benzene.

Hence, option $A$ is correct.

Suggest Corrections

Similar questions

H N O_{3}

H_{2} S O_{4}

In the nitration of benzene using a mixture of conc. H₂SO₄ and conc. HNO₃ the Species which initiates the reaction is_______________

H N O_{3}

H_{2} S O_{4}

In the nitration of benzene with a mixture of conc $H N O_{3}$ and conc $H_{2} S O_{4}$ , the active species involved are

N - O

N O_{2}^{+}

N O_{2}^{-}

N O_{3}^{-}

Join BYJU'S Learning Program