The activity of a radioactive sample is 1.6 curie and its half life is 2.5days. Then activity after 10 days will be:
A
0.16 curie
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B
0.8 curie
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C
0.1 curie
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D
0.4 curie
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Solution
The correct option is C0.1 curie The half life is 2.5 days. After every 2.5 days its activity reduces to half the value. Also, 10 days =102.5=4 half life periods. The initial activity of a radioactive sample is 1.6 curie The activity after 10 days will be 1.6×(12)4=1.6×116=0.1 curie.