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Question

The activity of a radioactive sample is measured as 9750 counts (minute)1 at t=0 and 975 counts (minute)1 at t=5 minute. The decay constant is nearly

A
0.922min1
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B
0.691min1
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C
0.461min1
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D
0.230min1
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Solution

The correct option is C 0.461min1
activity after timet is N=N0eλt
where N0 is activity at t=0 putting the above values we get
  • decay constant λ=0.461min1
  • use λ=(1/t)logeN0N and loge10=2.303

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