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1st Law of Thermodynamics

The activity ...

Question

The activity of the hair of an egyptian mummy is $7$ disintegration $m i n u t e^{- 1}$ of $C^{14}$ . Find the age of mummy. Given $t_{0.5}$ of $C^{14}$ is $5770 y e a r$ and disintegration rate of fresh sample of $C^{14}$ is $14$ disintegration $m i n u t e^{- 1}$ .

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Solution

$t = \frac{2.303 \times 5770}{0.693} \times l o g (\frac{14}{7})$
$t = 5770$ years

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