The activity per ml of a solution of radioactive substance is x. How much water be added to 200 ml of this solution so that the activity falls to x/20 per ml after 4 half-lives?
A
100 ml
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B
150 ml
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C
80 ml
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D
50 ml
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Solution
The correct option is C 50 ml The initial activity is x×200. Let V ml be the volume of the solution. The activity after four half-lives is =x20×V.
N=N0(12)n
(xV20)=(x×200)(12)4
Thus the final volume is 250 ml. Hence, 50 ml of water is added.