The actual weight of a molecule of water is :

18

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2.99 \times 10^{- 23}

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both A and B are correct

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none of these

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Solution

The correct option is D $2.99 \times 10^{- 23}$ g
Weight of $N_{A}$ molecule of water is = $18$ g
Weight of $1$ molecule of water is = $\frac{18}{N_{A}} g$

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Similar questions

The gram molecular mass of water is 18 g. The number of water molecules present in 60 g of water is:

C_{60} H_{22}

C_{60} H_{122}

6.02 \times 10^{23}

6.68 \times 10^{23}

6.09 \times 10^{22}

6.022 \times 10^{23}

6.022 \times 10^{21}

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