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Numbers in General Form

The addition ...

Question

The addition of $121$ and its reverse is

241

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242

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243

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None of the above

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Solution

The correct option is A $242$
The reverse of $121$ is $121$
$∴ 121 + 121 = 242$

So, option B is correct.

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25^{\circ} C

(C_{6} H_{10})

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- 241, - 3800

- 3920 K J / m o l e

\sqrt{2} + \sqrt{6} + \sqrt{18} +

121 (\sqrt{6} + \sqrt{2})

243 (\sqrt{3} + 1)

\frac{121}{\sqrt{3} - 1}

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99

121

x^{5} + 242 = \frac{243}{x^{5}}

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