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Question

The addition of HBr is easiest with

A
ClCH2=CHCl
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B
ClCH=CHCl
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C
CH3CH=CH2
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D
(CH3)2C=CH2
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Solution

The correct option is D (CH3)2C=CH2
d) It is a unsymmetrical Olefin.In such cases addition of HX is governed by 'Markovnikoff's rule'.

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