The addition of HBr is easiest with:

{C H}_{2} = C H C l

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C l C H = C H C l

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{C H}_{3} - C H = {C H}_{2}

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{({C H}_{3})}_{2} C = {C H}_{2}

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Solution

The correct option is D ${({C H}_{3})}_{2} C = {C H}_{2}$

Addition of $H B r$ to alkene involves the formation of carbocation intermediate. Thus anything which increases the electron density around the double bond will ease the reaction.
(Refer to Image)
The carbocation is stabilized by the presence of alkyl group due to $+ I$ effect.
Hence the addition of $H B r$ is easiest with $(C H_{3})_{2} C = C H_{2}$ .

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