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Zinc II Oxide

The addition ...

Question

The addition of $N a O H$ to $Z n^{2 +}$ ion gives a white precipitate which on the addition of excess $N a O H$ dissolves the precipitate. In this solution, $Z n$ exists in:

A

Z n^{2 +}

form

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B

Cationic form

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C

Anionic form

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D

Both (b) & (c)

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Solution

The correct option is C Anionic form
$Z n^{2 +} + N a O H \to Z n (O H)_{2} (w h i t e p p t) (↓)$

$Z n (O H)_{2} + N a O H (e x c e s s) \to [Z n (O H)_{4}]^{2 -} (s o l u b l e c o m p l e x)$

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