Question

The addition of pyridinium ion $C_5{H}_5{NH}^{+}$ on the position of the equilibrium. The $pH$ will be ?

• A. Decrease
• B. Increase
• C. No change
• D. Can't say

Answer 1

Answer: (A)

Decrease

As we add pyridinium ion at eqm, equilibrium shifts towards backside

$C_5{H}_{5}N+\left[H^{+}\right]=\to C_5{H}_{5}N{H}^{+}$

The solution will have more no of hydrogen ion in solution so pH of solution decreases.

($\because pH=-log\left[H^{+}\right]$)